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Example 1 (Continued)

limn→∞ 1 = 1, converges, because aH = 1 for all H.

limn→∞ n - 2 = ∞, diverges, because H - 2 is positive infinite for all H.

limn→∞( - 2n) = - ∞, diverges, because -2H is negative infinite for all H.

limn→∞ (-1)n is undefined, diverges, because(-1)2H = 1 but(- 1)2H+1 = - 1.

limn→∞ 1/n = 0, converges, because 1/H has standard part zero.

                                                               


Last Update: 2006-11-15