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Theorem 1: Sequences approaching ∞

THEOREM 1

Each of the following sequences approaches ∞.

limn→∞ n! = ∞,

limn→∞ bn = ∞ if b > 1,

limn→∞ nc = ∞ if c > 0,

limn→∞ ln(n) = ∞.

Moreover, each sequence in the list grows faster than the next one,

(i) 09_infinite_series-19.gif (b > 1),

(ii) 09_infinite_series-20.gif (b > 1, c> 0),

(iii) 09_infinite_series-21.gif (c > 0).

PROOF

Let H be positive infinite. We already know that ln H is positive infinite. We must show that each of the following are also positive infinite.

09_infinite_series-22.gif

It is easier to show that their logarithms are positive infinite. We need the fact that, by l'Hospital's rule for ∞/∞,

09_infinite_series-23.gif

so 09_infinite_series-24.gif for all infinite K.

(i) 09_infinite_series-25.gif. Let m > b. Then

09_infinite_series-26.gif = ln 1 + ... + ln (m - 1) + ln m + ... + ln H - H ln b

> (H - m) ln m - H ln b = H(ln m - ln b) - m ln m. Since m > b. ln m > ln b, and ln (H!/bH) is positive infinite.

(ii)09_infinite_series-27.gif

09_infinite_series-28.gif

Since b > 1, ln b > 0. (ln H)/H is infinitesimal. Therefore ln(bH/Hc) is

positive infinite, (iii) 09_infinite_series-29.gif. Let K = ln H.

09_infinite_series-30.gif

Since c > 0, K is infinite, and (ln K)/K is infinitesimal, ln(Hc/ln H)) is positive infinite.

Note: For n = 1, the term nc/(ln n) is undefined, so we should start the sequence with n = 2.

Example 8: Sequences Approaching ∞

COROLLARY

(i) limn→∞ b-n = 0 if b > 1.

(ii) limn→∞ n-c = 0 if c > 0.


Last Update: 2006-11-07