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Example 7

Find an error estimate for the power series for ln((1 + x)/(1 - x)) valid for - c ≤ x ≤ c. Use it to approximate ln 2 within 0.00001.

From Example 5 we have the following error estimates for in (l + x) and - ln (1 - x) valid for - c ≤ x ≤ c.

09_infinite_series-656.gif

We add the two sums and error estimates,

09_infinite_series-657.gif

We wish to choose x so that (1 + x)/(l - x) = 2. Solving for x we get x = ⅓. Now set c = 5 and x = ⅓. The error estimate for x = ⅓ is

09_infinite_series-658.gif

Table 9.9.2

m

09_infinite_series-659.gif

Approximate value for ln 2

09_infinite_series-660.gif

Error estimate

09_infinite_series-661.gif

1

0.666667

0.666667

0.037037

2

0.024691

0.691358

0.002469

3

0.001646

0.693004

0.000196

4

0.000131

0.693134

0.000017

5

0.000011

0.693146

0.000002

The error estimate drops below 0.00001 when m = 5. Thus ln 2 ~ 0.693146, error ≤ 0.00001.


Last Update: 2006-11-15