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Home Vectors Planes in Space Examples Example 9: Line Perpendicular to a Plane | |
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Example 9: Line Perpendicular to a Plane
Find the line L through the point P(1, 2, 3) which is perpendicular to the plane 3x - 4y + z = 10. The plane has the normal vector N = 3i - 4j + k. Therefore N is a direction vector of L, and L has the vector equation X = P + tN, X = i + 2j + 3k + t(3i - 4j + k) (see Figure 10.5.11). Figure 10.5.11
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Home Vectors Planes in Space Examples Example 9: Line Perpendicular to a Plane |