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Resistance of a lightbulb
Question: A flashlight bulb powered by a 9-volt battery has a resistance of 10 O. How much current will it draw? Solution: Solving the definition of resistance for I, we find I= ΔV / R = 0.9 V/Ω = 0.9 V/(V/A) = 0.9 A
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| Home Electricity Circuits Examples Resistance of a lightbulb |
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