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Home Applications of the Integral Improper Integrals Examples Example 10 |
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Example 10
Find We see that
and
Thus
Figure 6.7.10 It is tempting to argue that the positive area to the right of the origin and the negative area to the left exactly cancel each other out so that the improper integral is zero. But this leads to a paradox. Wrong:
Let v = x + 2, dv = dx. Then
Subtracting
But
So we do not give the integral
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Home Applications of the Integral Improper Integrals Examples Example 10 |
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