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Proof of Theorem 1

PROOF OF THEOREM 1

The plan is to prove a corresponding result for average slopes and then use the Mean Value Theorem, which states that the average slope of a function on an interval is equal to the slope at some point in the interval.

Let Δx and A31 be positive infinitesimals. We hold Δx and Δy fixed. The first and second partial derivatives of f(x, y) exist for (x, y) in the rectangle

a ≤ x ≤ a + Δx, b ≤ y ≤ b + Δy.

We shall use the following notation for average slopes in the x and y directions:

11_partial_differentiation-546.gif

Label the corners of the rectangle A, B, C, and D as in Figure 11.8.1.

11_partial_differentiation-547.gif

Figure 11.8.1

We first show that the following two quantities are equal:

11_partial_differentiation-548.gif11_partial_differentiation-549.gif

A2f/Δy Δx is the average slope in the y direction of the average slope in the x direction of f

11_partial_differentiation-550.gif

By the Mean Value Theorem,

11_partial_differentiation-551.gif

where b ≤ yl ≤ b + Δy. Using the Mean Value Theorem again,

11_partial_differentiation-552.gif

where a ≤ xl ≤ a + Δx. Since ∂2f/∂x ∂y is continuous at (a, b),

11_partial_differentiation-553.gif

A similar computation gives

11_partial_differentiation-554.gif

Therefore

11_partial_differentiation-555.gif


Last Update: 2010-11-25