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Home DC SeriesParallel Combination Circuits Redrawing complex schematics  
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Redrawing complex schematicsRedrawing schematic diagramsTypically, complex circuits are not arranged in nice, neat, clean schematic diagrams for us to follow. They are often drawn in such a way that makes it difficult to follow which components are in series and which are in parallel with each other. The purpose of this section is to show you a method useful for redrawing circuit schematics in a neat and orderly fashion. Like the stagereduction strategy for solving seriesparallel combination circuits, it is a method easier demonstrated than described. Let's start with the following (convoluted) circuit diagram. Perhaps this diagram was originally drawn this way by a technician or engineer. Perhaps it was sketched as someone traced the wires and connections of a real circuit. In any case, here it is in all its ugliness: With electric circuits and circuit diagrams, the length and routing of wire connecting components in a circuit matters little. (Actually, in some AC circuits it becomes critical, and very long wire lengths can contribute unwanted resistance to both AC and DC circuits, but in most cases wire length is irrelevant.) What this means for us is that we can lengthen, shrink, and/or bend connecting wires without affecting the operation of our circuit. The strategy I have found easiest to apply is to start by tracing the current from one terminal of the battery around to the other terminal, following the loop of components closest to the battery and ignoring all other wires and components for the time being. While tracing the path of the loop, mark each resistor with the appropriate polarity for voltage drop. In this case, I'll begin my tracing of this circuit at the negative terminal of the battery and finish at the positive terminal, in the same general direction as the electrons would flow. When tracing this direction, I will mark each resistor with the polarity of negative on the entering side and positive on the exiting side, for that is how the actual polarity will be as electrons (negative in charge) enter and exit a resistor:
Any components encountered along this short loop are drawn vertically in order: Now, proceed to trace any loops of components connected around components that were just traced. In this case, there's a loop around R_{1} formed by R_{2}, and another loop around R_{3} formed by R_{4}: Tracing those loops, I draw R_{2} and R_{4} in parallel with R_{1} and R_{3} (respectively) on the vertical diagram. Noting the polarity of voltage drops across R_{3} and R_{1}, I mark R_{4} and R_{2} likewise: Now we have a circuit that is very easily understood and analyzed. In this case, it is identical to the fourresistor seriesparallel configuration we examined earlier in the chapter. Let's look at another example, even uglier than the one before: The first loop I'll trace is from the negative () side of the battery, through R_{6}, through R_{1}, and back to the positive (+) end of the battery: Redrawing vertically and keeping track of voltage drop polarities along the way, our equivalent circuit starts out looking like this: Next, we can proceed to follow the next loop around one of the traced resistors (R_{6}), in this case, the loop formed by R_{5} and R_{7}. As before, we start at the negative end of R_{6} and proceed to the positive end of R_{6}, marking voltage drop polarities across R_{7} and R_{5} as we go:
Now we add the R_{5}
We repeat the process again, identifying and tracing another loop around an alreadytraced resistor. In this case, the R_{3}
Adding the R_{3} With only one remaining resistor left to trace, then next step is obvious: trace the loop formed by R_{2} around R_{3}: Adding R_{2} to the vertical drawing, and we're finished! The result is a diagram that's very easy to understand compared to the original: This simplified layout greatly eases the task of determining where to start and how to proceed in reducing the circuit down to a single equivalent (total) resistance. Notice how the circuit has been redrawn, all we have to do is start from the righthand side and work our way left, reducing simpleseries and simpleparallel resistor combinations one group at a time until we're done.
In this particular case, we would start with the simple parallel combination of R_{2} and R_{3}, reducing it to a single resistance. Then, we would take that equivalent resistance (R_{2}//R_{3}) and the one in series with it (R_{4}), reducing them to another equivalent resistance (R_{2}//R_{3} From there we could calculate total current from total voltage and total resistance (I=E/R), then "expand" the circuit back into its original form one stage at a time, distributing the appropriate values of voltage and current to the resistances as we go.


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